![]() So it’s not like Julia is the odd one out here. transposing it produces a special transpose (or in the case of ' an adjoint) vector, which is ‘row-like’. ![]() A matrix of this shape is often referred to as a row vector. That is, AB is typically not equal to BA. => X(1,:)*X(1,:)' returns a 1x1 matrix (‘scalar’-like) The size of the resulting matrix is 1-by-4 because it has one row and four columns. For nonscalar A and B, the number of columns of A must equal the number of rows of B.Matrix multiplication is not universally commutative for nonscalar inputs. Accepted Answer: Jos (10584) Hi, I have to convert a matrix in one column/row vector composed of all the rows of the original matrix.multiplication with * is a linear algebra operation How about this to convert the matrix into a column vector param2 data2d(:,1) Convert column 1 of 2-d data matrix into a column vector.‘row slice’ produces a 1xN matrix, not a vector.User beaker pointed out that an even simpler (though a bit obscure) syntax works in recent versions of MATLAB. If the mathematics are not important and any procedure will do, the easiest approach would likely be something like: Theme. multiplication with * is element-by-element and broadcasting, not a linear algebra operation The call to repmat repeats the vector V by the number of rows in M.transposing a flat vector does nothing, the vector is unchanged The call to repmat repeats the vector V by the number of rows in M.First of all, numpy does not return a row vector, but a flat vector like Julia: In : X.shapeĪlso, you should note that Matlab and numpy disagree with each other (as well as with Julia) in other ways: python and matlab however return a row vector (or a 1xN matrix) What size should the result be and why? in python and matlab (and julia), X will select a row.
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